Men's Basketball Tiebreaker Scenarios for the American Athletic Conference Championship|
March 6, 2014
American Athletic Conference Men's Basketball Tiebreaker Scenarios
The University of Cincinnati men's basketball team plays at Rutgers on Saturday (Noon ET, ESPNews/700 WLW) with the American Athletic Conference regular-season championship on the line. A victory over the Scarlet Knights gives the Bearcats at least a share of their first conference title since 2003-04.
Cincinnati is 25-5 overall and 14-3 in the conference entering Saturday.
Louisville welcomes UConn on Saturday (2 p.m. ET, CBS). The Cardinals are also 25-5 overall and 14-3 in the league.
Following are tiebreaker scenarios to determine the regular-season champion and the conference tournament's top seed according to the league office. The American Athletic Conference Championship is March 12-15 at the FedEx Forum in Memphis, Tenn.
If one team wins and the other loses Saturday, then the winner is the outright regular-season champion and the No. 1 seed.
If both teams win, then the SMU-Memphis game comes into play. If Louisville, Cincinnati and SMU win, then Louisville gets the top seed (would be 4-0 against SMU/UConn, while Cincinnati would be 2-2).
If Louisville, Cincinnati and Memphis win, then a coin flip will determine the 1/2 seeds. Both UC and UofL would be 4-2 against the group of SMU/UConn/Memphis, which would be tied at 12-6.
If both teams lose, then Louisville is No. 1 if SMU beats Memphis (UofL 3-1 vs SMU/UConn; Cincinnati is 2-2) and Cincinnati is No. 1 if Memphis beats SMU (Cincinnati 3-1 vs SMU/Memphis; Lou 2-2).
Any teams that tie for first place are declared regular-season champions, regardless of seed.